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https://www.hackerrank.com/challenges/java-datatypes/problem?isFullScreen=true


Solution

import java.util.*;
import java.io.*;

class Solution {
    public static void main(String[] argh) {
        Scanner sc = new Scanner(System.in);
        int t = sc.nextInt();

        for (int i = 0; i < t; i++) {
            try {
                long x = sc.nextLong();
                System.out.println(x + " can be fitted in:");
                if (x >= -128 && x <= 127) {
                    System.out.println("* byte");
                }
                if(x >= -Math.pow(2, 15) && x <= Math.pow(2, 15) - 1) {
                    System.out.println("* short");
                }
                if (x >= -Math.pow(2, 31) && x <= Math.pow(2, 31) - 1) {
                    System.out.println("* int");
                }
                if (x >= -Math.pow(2, 63) && x <= Math.pow(2, 63) - 1) {
                    System.out.println("* long");
                }
            } catch (Exception e) {
                System.out.println(sc.next() + " can't be fitted anywhere.");
            }

        }

        sc.close();
    }
}

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